2/3x^2+8/9x=1/6

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Solution for 2/3x^2+8/9x=1/6 equation: 


x in (-oo:+oo)

(2/3)*x^2+(8/9)*x = 1/6 // - 1/6

(2/3)*x^2+(8/9)*x-(1/6) = 0

(2/3)*x^2+(8/9)*x-1/6 = 0

2/3*x^2+8/9*x-1/6 = 0

DELTA = (8/9)^2-(-1/6*2/3*4)

DELTA = 100/81

DELTA > 0

x = ((100/81)^(1/2)-8/9)/(2/3*2) or x = (-(100/81)^(1/2)-8/9)/(2/3*2)

x = 1/6 or x = -3/2

x in { -3/2, 1/6 }

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